Boolit Going to Sleep?

Started by Nelsdou, August 07, 2010, 09:56:01 PM

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Nelsdou

I recently acquired a custom mould for the 8x57 Mausers that is a gas-checked sihouette style, single lube groove, and weighs in at 196 grains.  Fits my military Mauser throats snug and I like having the lube groove captured within the case neck. Very similar to the RCBS sihouette design.

Loaded a set of twenty up with a fairly brisk charge to push 'em fast, faster than I would expect good accuracy at but thought it worth experimenting since these pills fit the throat so well.

After printing ten on paper at 100 yds I was disappointed with a 9 inch scattergun group. My luck at pulling cast boolits from loaded cartridges has been dismal, often ending up with damaging the boolits beyond re-use so I decided to "unload" the remaining ten rounds by sending them down range at a 12 inch steel gong at 220 yds.

Lo and behold I nailed that steel gong ten out ten times.

Could this be a case where the boolit is taking some time going down range to stablize, hence, "going to sleep"?

The lube I use is Lars Carnauba Red which is fairly stiff but not sure if that could be a factor or not. My next thought is to back off on the charge slightly and see what happens.

Nels
Put it into perspective; we live on a rock hurtling through space, what could be scarier than that?

gitano

I've never been a proponent of the concept of a bullet "going to sleep" because I simply can't find a physical explanation for it. However, I keep a open mind about it because I hear about it's 'observation' from reliable sources. The 'observations' are all akin to what you describe above. Clearly, something is "going on", but what the cause is can't be easily observed or specifically replicated.

With regard to pulling cast bullets, have you tried and inertial puller? For soft-nosed bullets, I stuff the chamber with cotton, and take a series of lighter taps. I can't recall unloading any cast bullets, (I have a tendency to "unload" them downrange too :) ), but I'd be surprised if you couldn't get the noses to stay "perfect" at least. However, I think they may still be deformed by the seating or unseating process, especially if they have been crimped.

If you get a chance, could you post a picture of the cast bullet?

Thanks,
Paul
Be nicer than necessary.

gitano

By the way, it's encouraging to a cast boolit novice like me to hear of an experienced cast boolit shooter having the kind of luck I usually have with getting cast boolits to shoot straight.

Paul
Be nicer than necessary.

recoil junky

My sleeping bullet experience wasn't with cast bullets, but I have been down that road with jacketed bullets. I was in Paul's camp of "non-believers" until I saw it for myself.

All it took to get the bullet back on the right path was to drop the powder charge a bit and everything was happy.

I can't see what the difference between it happening with a cast bullet or jacketed bullet would be. They are both mostly lead right? I had my sleeping bullet trying to make a rifle shoot another rifles pet load and seein's as how I need my varmint rifles to shoot eensy teensy groups throughout their useful trajectory, it behooves me to try anything to make them do it.

Also have a similar situation occurring with the 300RUM. I'm not sure at this point what to make of it or how to cure it, so it (the rifle) is going to just have to deal with it. At 200 yards my groups are the same size if not a tad smaller than a 100 yard group. In all reality groups should get bigger the longer the distance.

Right?

RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

gitano

Here's the problem I have with bullets "going to sleep":

What force acts on the bullet to REDUCE runout?

Bodies in motion do not change their motion without a force being applied. (Ya just can't violate the laws of physics.) Once the bullet leaves the barrel, what forces are 'available' to act on the bullet to get it to  CONSISTENTLY change its motion. The only forces I am aware of are wind and gravity. Wind is random, NOT consistent, and while gravity is constant, it is constantly in one direction - "down". So... Tell me what what force makes a bullet's angular deviation from line of flight get smaller?

I don't doubt the veracity of the observations, but I do question the completeness of the "experiments". In order for me to be convinced that a bullet can "go to sleep", I would have to see repeated experiments where all variables were kept the same. In Nels' example, the information we don't have is the actual distribution of the "9 inch scattergun group" and the distribution of the hits at 220 on the 12" gong. I can think of several circumstances that explain the variation between those two observations that doesn't include the invocation of a mysterious external force. (Although I too would have expected mostly misses based on the initial 100-yd group.)

In RJ's example, if I read it right, reducing the charge (muzzle velocity) eliminated the "sleeping". If that's the case, why would some force act in some cases and not others?

Because I continue to hear of examples of "smaller groups at longer ranges" from reputable sources, I maintain an open mind regarding "sleeping" bullets. But I also maintain a high level of skepticism because I can find no explanation that doesn't violate the fundamental laws of motion in the universe as we know it, AND, I have seen no one else provide such an explanation.

I'd bet dollars-to-donuts that Nels' groups tighten up when the muzzle velocity slows down.

Paul
Be nicer than necessary.

recoil junky

The question still remains though . . . . .

WHY IN THE $#&& does my 300RUM groups get smaller/stay the same size (in area, not m's oa) as distances double. It's SUPPOSED to happen!!!! By the laws of nature and physics it's SUPPOSED to happen. Oh yes I know a minute of angle get's "bigger" as far as size in square inches, but that's not what I mean. A rifle that shoots miserable 1/2-3/4 moa groups at one hundred yards should in all reality shoot those same groups at 200, 300, yadda yadda yadda yards NOT not in area BUT IN MOA.

So you see my point. A rifle that can put x number of shots under a dime at 100 yards and keep them there out to 200 yards (OK a nickle at 200) is bending if not breaking the laws of physics.

Am I complaining? NOT HARDLY

RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

Daryl (deceased)

I dunno what to believe any more, but just to be safe, I think I'll start checking my bullets before I fire them to be sure they're awake!
 
Imagine waking up, doing 3100 fps at a solid object.  It's no wonder they dodge a bit along the way.
 
:)
 
Daryl
A government that abrogates any of the Bill of Rights, with or without majoritarian approval, forever acts illegitimately, becomes tyrannical, and loses the moral right to govern-Jeffrey Snyder
 

RIP Linden33

gitano

:) :) :)

I dunno, RJ. It's because I believe folks like you that I keep an open mind on the matter.

But it's a complicated matter. Just going one distance point to another doesn't really address the "why". Using your "dime" at 100 and nickel at 200 has some assumptions. If the 200 yd group is larger - AT ALL - then nothing "special" may be going on at all. Lemme 'splain.

In this case, I MUST differentiate between "accuracy" and "precision". Accuracy is the ability of a rifle AND THE SHOOTER to hit A SPECIFIC POINT IN SPACE. If a rifle/shooter combination can put 10 shots inside half an inch at 100 yards, but they can't hit the bullseye with any of those 10 shots because the 'scope is off, they're NOT ACCURATE. The RIFLE is VERY precise, but depending on how far off the bull they are, they could be extremely INACCURATE. Precision is "small groups"; accuracy is hitting exactly what you aim at with ONE (or many) shot(s). A rifle's precision is a constant. A person's precision is MOST CERTAINLY NOT constant.

OK, let's say you have a RIFLE that is VERY precise. In fact, it is so precise that if it was mounted in a mechanical grip, it could put 10 shots in the exact same hole at 100 yds. Then let's say that your are NOT capable of that level of precision. Let's say the best you can hold that rifle still is plus or minus about 0.001" (roughly 1 MOA at 100 yds). Next, you settle in to shoot a group at 100 yds and shoot a 1" group of 3 shots. Next, you move the target out to 200 yds and shoot a 3-shot group of 1.25 inches instead of the expected 2 inches. The bullets didn't "go to sleep", you are just seeing yourself holding "tighter". If the rifle was mounted in a mechanical stand, the 200 yd group would be exactly the same as the 100 yd group - namely all in one hole.

The point is: If you take the 100-yd group as a measure of the precision of the rifle instead of the precision of the rifle AND SHOOTER, you don't know whether the group's size was a function of the rifle's precision, or the shooter's 'wobbling'. If it was the shooter, group-to-group variation is moment-to-moment variation of the shooter's ability to hold still.

In other words, groups sizes not increasing with range are more likely to be the result of a rifle being significantly more precise than the shooter, than it is that some unexplained phenomenon like "sleeping bullets" is actually happening. Consider the extra-ordinarily small groups shot by people at 1000 yds. (I think the new world record 10-shot group is under 3".) That's the gun AND the shooter being VERY precise. Personally, I think "sleeping bullets" are more often than not just a REALLY precise rifle being shot by someone not as precise as the rifle.

Paul
Be nicer than necessary.

recoil junky

#8
I'll see your point and raise you this conundrum. :greentongue:
 
When using a dime and a nickle as group size the difference at 200 yards is, well, negilagable, right?
 
In the scheme of things if a rifle and shooter were capable of putting 5 shots (my theory of 5 vs. 3 later) in, say 1/2 moa at 100 yards (an area of roughly 1/2"X1/2"), in the theory of physics, the group should still be 1/2 moa or roughly an area of 1 square inch at 200 yards. Agreed?
 
My "sleeping bullet theory":
 
Once upon a time :rolleyes: this feller had a new rifle. He developed a group that shot 1/2 moa at 100 yards. When he took the rifle out to slay sabre toothed sage rats (stsr's) he discovered something very distubing. Out to 150 yards he was able to slay stsr's with great precsion. At distanced greater than 150 yards his percentage was, well, embarrassing. Good thing he was alone when he discovered this. So he went home and shot said rifle at 200 yards, finding that the groups were in excess of 2 moa (about 1.5 minutes of stsr) He then developed a load that was under 1" sq'd at 200 yards or 1/2 moa using .7 grain less powder. Upon shooting this same load at 100 yards, he was very displeased :Banghead: to find that it "splayed" out to 1 moa. (still well under 1 minute of stsr)
 
Unable to 'splain this phenomenon of "the sleeping bullet" to himself he made queeries to some fo his shooting and reloading friends and came up with this theory:
 
"If'n a rifle and shooter are capable of shooting one inch, 5 shot, groups at 200 yards don't mess with a good thing. You'll kill quite a few stsr's on a good day."
 
My theory of 3 shot vs. 5 shot vs. 10 shot groups:
 
"Any shooter can pull off a good three shot group most of the time. A five shot group tests not only the rifle but the shooter as well. A ten shot group prooves to the shooter that he and his rifle are capable of defending the rodent asault vehicle when the stsr's are coming right for you."
 
This does not hold true for rifles used in the taking of big game like deers 'n elks, (Unless of course they are saber toothed deers 'n elks) because you generally only need one shot. This is not to say that the rifle and shooter shouldn't be capable of 1/2 moa 5 shot groups.
 
RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

recoil junky

Oh, one minute of stsr equals 1 1/2 inches at any distance.
 
RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

gitano

#10
QuoteHe then developed a load that was under 1" sq'd at 200 yards or 1/2 moa using .7 grain less powder. Upon shooting this same load at 100 yards, he was very displeased to find that it "splayed" out to 1 moa. (still well under 1 minute of stsr

It REALLY depends on the number of shots fired. If the 200 yd group was "about" an inch at 200 yds (0.5 MA) and "almost" an inch at 100 yds, (1 MOA) then I would argue that the example essentially corroborates my point about the rifle being more precise than the shooter.

Now if the shooter were to shoot 100 rounds at 200 yds and 100 rounds at 100 yds and the statistical confidence intervals of the two groups were statistically significantly different, THEN I'd be fairly convinced that 'something funny' was goin' on and would have to go look for the force that was acting on the bullet in mid-flight. As presented, it seems perfectly reasonable to me, and doesn't lead me to consider that the "runout" of the bullet's flight path is getting smaller.

I think one of the problems we're all dealing with is the absolute "truth" that we all grew up reading from gunwriters (ptooey) about "accuracy". (They couldn't even get the term for what they were talking about right.) We've all had drilled into our heads that 1 MOA (1") at 100 yds = 1 MOA (2") at 200 yds = 1 MOA (3") at 300 yds, etc. THAT ASSUMES THAT THE SHOOTER HAS NO INFLUENCE ON THE PRECISION OF THE "SYSTEM". Put another way, it assumes that the rifle is the "weak link" in the "system's" overall precision. That's just plain wrong. Especially today. There are many rifles made that are capable of shooting more precisely than the shooters shooting them are capable of holding. When that's the case, group sizes at different ranges at different times are not going to follow the "law" that says 1 MOA at one range equals 1 MOA at a greater range.

Paul


PS
Here's a way to quantify the precision of a shooter:

Put a laser in the bore of the rifle in question and have the shooter hold the rifle on target for say 1 minute. (Light travels in a straight line as opposed to a bullet's arc, so range would be immaterial.) As the laser moves around the target, it would etch or other wise mark the paper. At the end of the test interval, the area 'scribed' by the laser would define the precision of the shooter. Then, no matter how precise the firearm was, the "system" of firearm and shooter could NOT do better than the shooter's measured precsion. IN FACT, it is highly likely that the variances would be multiplicative, not additive. Meaning that the "spread" would be the precision of the shooter TIMES the precision of the firearm.

In fact, it strikes me that this would be the perfect test of "sleeping bullets". Strap a laser on a rifle and "sight it in". Have the laser "fire" every time the trigger is pulled when firing a bullet. The laser's mark could then be compared to the bullet's hole. Done with just a few shots - say 5 - at each of a couple of ranges, and the "truth" of "sleeping bullets" could be determined.

The practical problem with the above experiment, is getting a laser strong enough to etch paper at even 100 yds, let alone 200.

Paul
Be nicer than necessary.

recoil junky

#11
Gun writers = double ptooety
 
But you see my point on the laws of physics vs. group size right?
 
I see and agree with your point on accuracy vs. precsion, which is why I refuse to shoot only 3 shot groups. 5 times the chance for error on the shooters part, 5 times the chance for precsion on the rifles part. 10 shots is even better because than we start to get the rifle hot and are likely to find out just how well the shooter and rifle can take heat and recoil. Good things to know when the stsr's are rabid and coming right for you and the rodent asault vehicle.


Hmmmm, a laser strong enough to "etch paper" might be strong enough to "etch/vaporize" stsr's. :jumpingsmiley:

If one could train a camera on the paper with the shutter open for one minute while the laser was also trained on the paper might be more feasable.

And yes the vairiences would be multiplied, I agree.

The one thing we are not taking into account though is that the shooter is going to wait and shoot between heart beats. Maybe. So, now we bring in the mechanical rest and remote trigger puller gizmawhicky.
 
 
RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

Nelsdou

Exhibit #1, a couple of the 196 grain GC boolits next to a couple of 150 grain plain base ones. The 196's are from a mould cut by BRP.



Although it's hard to see the 196's have a small flat on the nose, then swell to .316 in diameter, then gradually grow to .325 before approaching the lube groove. This fits my Mausers' throats exceptionally well. For a cast boolit the BC shouldn't be too shabby.

My next chance I'll reduce the charge slightly and see the effect. I'd like to keep the velocity on these babies as high as I can accurately push them and possibly be a candidate for longer ranges.

One other factor worth mentioning would be "seasoning the barrel". My experience has been one or two foulers is all that's needed but some claim more are needed. I find it unlikely that it would take 10 foulers before settling in a load, but who knows? I've never had cast boolits shoot that well over 200 yds yet. I guess next time I could shoot 10 at 200 yds on paper first then shoot 10 at 100 yds to see a difference.

Nels
Put it into perspective; we live on a rock hurtling through space, what could be scarier than that?

recoil junky

Nels, I think less velocity is the answer.

In going back and rereading Paul's and my tirades and rants, Paul asked "What force acts on a bullet to reduce run-out" and I believe (and from what I'm gleaning from Paul's notes, from here and other threads) it's RPM. So by reducing muzzle velocity, we've reduced RPM, making the bullet more stable. I may be wrong about this as related to bullets, but my thinking comes from spinning masses like drivelines and the like.

That is a dandy looking bullet by the way. A sway away from the multi lube groove bullets of old, but from your description, the "bearing surface" is about 1/3-1/2 the bullet length? The other bullet is akin to my 458124 that I'm using in my 45-70.

What's your alloy?

RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

gitano

Quoteit's RPM

Nope...

I was anticipating that argument. The primary reason that "nope" is the response is that the angular momentum of the bullet is the force that must be overcome by the "mysterious" force.

Also, of critical importance is the fact that the bullet is essentially spinning on an air bearing. As bearing materials go, there are precious few in the world that have less resistance than air. I discussed this at length with a couple of the nation's leading ballisticians AND some very savvy mechanical engineers. All agree without qualification that a bullet's rpms at impact - whatever the distance - are essentially exactly the same as they were when the bullet left the barrel. So there's no "slowing down" of the angular velocity or diminishing of the angular momentum of a spinning bullet - especially at ranges even as long as 2000 yds.

To prove this to yourselves (the collective "you") buy yourself a top or a toy gyro. Neither of those have "air" bearings. (The top's bearing is the surface on which it is spinning and the gyro's bearing is the metal frame in which it spins.) Nonetheless, observe their rotation two seconds after you start their spinning. It is indistinguishable from the initial velocity, and they don't have air bearings.

Now, consider how far a bullet would travel in 2 seconds - at 3000 f/s, it's A LONG WAY. Furthermore, it's initial rotational velocity (expressed as rpms) is on the order of 200,000. (A rifle with a twist rate of 1:12 will spin a bullet doing 3000 f/s at 180,000 rpms. One rotation in one foot - 3000 feet in one second - 60 seconds in a minute.) That's s bit faster than you can spin a top or a gyro.

Now consider how long it takes a bullet to travel from the 100 yd target to the 200 yds target - about 0.04 seconds for a "typical" hunting bullet. It's clear that the rpms don't slow in that interval of time, especially on an air bearing.

Even if the angular velocity did diminish enough to STOP the INCREASING deflection, for the bullet's "runout" to DIMINISH, some force would have to act on the bullet. In other words, once the bullets angular momentum stopped "pushing" it out of alignment with the line of sight, something would have to push it back in, in order for it to get smaller.

By the way, we haven't even discussed the "input" to the "system" from variance in bullet weight AND balance. The reason we haven't is because it is assumed to be negligible. Maybe that's a reasonable assumption with today's jacketed bullets and maybe not. 200,000 rpms invoke considerable momentum even to something as small in diameter as a bullet.

As an aside, the reason I was discussing rpms with expert ballisticians and engineers is that I was arguing with some nimrod that was trying to say that the reason bullets "lost accuracy" at "long ranges" was because they lost their gyroscopic stability (gs). They can't lose their gs if they're still spinning as fast as they were when they left the muzzle - and they are. What causes loss of "accuracy" at long ranges is the bullet transiting the sound barrier. There is considerable turbulence associated with crossing the sound barrier going in either direction. That's why long-distance target shooters - 600 yds and longer - want their bullets to have high ballistic coefficients - so they retain their super-sonic velocity longer. At least to the range of the target.

Paul
Be nicer than necessary.

recoil junky

I understand the "air bearing" is as close to being "without friction" as it is possible to get here on earth.

I understand gyroscopic stability (gs) even on something as small as a bullet.

I thought we went into the "rpm's thing" when that video came out of  all the bullets hitting that steel plate, where you could see the spin of the bullet but maybe I misunderstood. I've been known to do that from time to time.

What I'm getting at by saying "rpm's" is from watching a driveshaft being balanced. An imperfect driveshaft (as with cast bullets, no two of which are the same) has certain points in the rpm range before it's balanced where it "acts" balanced. In other words it doesn't vibrate at all. So, (I think) a bullet is the same way. No one at the bullet factory balances bullets as they drop off the little belt and into boxes, the same as Nels and I (and YOU) don't balance our cast bullets. We sort through them, weigh a few and the ones that look "bad" or are "too light" are thrown back into the pot and made into "good" bullets.

It's those "imperfections" we are trying to balance out by changing the velocity, hence the rpm's.

RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

Nelsdou

These are all Lyman #2 alloy I bought on one of those $13/box shipping specials that makes my postman fond of me :grin:.

I dunno. I've never had a bullet get better going down range, but something happened when I switched from 100 to the 220 yd gong. BTW there was hardly a breeze stirring while shooting. A rare day.

When I get poor results at 100 yds, it's usually vertical spreading or horizontal spreading with a consistency to it and I have an idea what is going on. But when I get holes in the paper in all four quadrants around the POA my conclusion is that there is a variable "out of control" that has to be fixed before going any further. In this case since I was already pushing pressure and velocity (actually acceleration) I figured the bullet was getting distorted and out of balance leaving the muzzle, so I was resigned to drop the charge some, even before I decided to "unload" at the gong.

I've got 20 ready to go at the same charge and plan to load more at a slightly reduced charge. Angular velocity difference should be minimal.  We'll see what happens.

Nels
Put it into perspective; we live on a rock hurtling through space, what could be scarier than that?

Jamie.270

Using Pauls analogy of the top, consider this a moment.  I have seen and maybe some of you have too, a top that isn't launched exactly on it's axis.  As a result it wobbles for a second before it's momentum(s) are stabilized or are overcome by gyroscopic effect, and the top stops wobbling and stabilizes on it's axis.
Now, as to what may destabilize the bullet slightly as it leaves the muzzle?  I would say it's muzzle blast, or the blowby of gasses and unburnt powder.  While these aren't enough to completely destabilize the bullet (tumble), they may be enough to induce a slight yaw in the bullet's attitude, relative to it's trajectory.  
This yaw, when induced during initial free travel is enough to cause the uneven air (wind) resistance to alter it's course slightly.
As the bullet travels further downrange, the gyroscopic forces (and possibly air [wind] resistance) serve to stabilize the bullet the same way they do the top.
Decreasing the powder charge may eliminate the problem, as has been witnessed.  
But I believe it is the corresponding reduction in "blowby" or "muzzle blast" that gives the desired results.

Something about bullet yaw and pitch, by Bryan Litz of Berger Bullets:
http://www.youtube.com/watch?v=KH9SCbCBHaY
QuoteRestrictive gun laws that leave good people helpless, don\'t have the power to render bad people harmless.

To believe otherwise is folly. --  Me

gitano

Now that's an interesting comparison...

While I have no experience to draw on for drive shafts per se (other shafts though), I can relate to wheels having balance points that are a function of rpms. I can see where a shaft could have multiple rpm 'nodes' where it was "balanced" and those in which it was "unbalanced". That wouldn't explain "sleeping bullets", but it would further explain why some bullets "like" some muzzle velocities (MV translating directly to rpms).

The reason this wouldn't explain "sleeping bullets" is that the rpms don't change enough in 100 yds or so to cause the bullet to move off of an "unbalanced rpm node". At least the experts don't think so, and I agree with them.

Actual rpm could be measured from those hi-speed videos. To actually measure the difference over a realistic range, the bullet would have to be photographed at the muzzle and at say 100 yds.

Still, it doesn't "add up". 180,000 rpms is 3000 revolutions per second, and 120 revolutions in 0.04 seconds. Which is roughly the time it would take a bullet with a MV of 3000 f/s to travel from 100 to 200 yds - the "going to sleep place".)

I'll give this some more thought.

Paul
Be nicer than necessary.

recoil junky

#19
And thinking on this as "mass in motion" (mim) the smaller the mass, ie. a bullet, the faster it can be spun. Therefore (a big word for this bumpkin) the fewer rpm's it takes to "upset the balance" as it comes closer to hitting one of those nodes.

Nodes, that was the word I was looking for. Thanks Paul.

And I've had the "tire balancing" mystery happen to me. At certain speeds the unbalanced tire/wheel assembly will hit one of these nodes and act as if balanced perfectly. Often there are more than two of these nodes, but I've only experienced two myself. I was too scared to drive Dad's '73 F250 faster than 70 mph with it's 750/16, 10 ply bias tires.

An 11R24.5 tire's out of balance phase(s) is/are more noticeable than say a P185-70R13 tire's because of the mim.

So, IMO, this can be translated to a bullet (or boolit) but on a much smaller scale. If the bullet (boolit) is "balanced" at 181,234 rpm, but isn't at say 181,232 rpm it could be in one of those nodes.

Kinda like a girl. They can go from calm, kind and loving to high speed come-apart in less than 1 rpm.

RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

gitano

All of this conversation got me to 'working' on this issue in depth again, and I think Jamie.270 and RJ have struck upon the causes of the phenomenon. The top analogy is right on - with one caveat - I think.

When throwing a top, the string and the smoothness with which it is thrown determine whether and how much it wobbles at the start. However, the law of conservation of momentum dictates that the top will stabilize at some point if the initial perturbations aren't too great. So... taking the analogy to bullet flight, if the perturbations at the point the bullet leaves the muzzle are 'great', it will take a while for the angular momentum of it's rotation to stabilize it. In this case, the bullet might print a relatively 'large' group at 100 yds, and a relatively "small" group at 200 yds, BUT NOT SMALLER.

One problem that still remains for me in this analogy is that the top has a fixed point of contact with an immovable surface. The bullet does not. Therefore, the bullet has no reference point/attachment against which its momentum can act. At least not one I can envision at the moment. More thought required on that issue.

While this removes a great deal of my skepticism, a small amount remains. (I'm just hard-headed.) ALL the unexplained elements need to be explained before I'll acquiesce to "sleeping bullets", but as I said, this takes care of most of them.

As to Berger's video... There's a GREAT deal of the initial conditions that are left unexplained. For example:

1) What exactly are the 6 degrees of freedom?
2) In a rotating object with no reference point, like a bullet in free flight, the "pitch" and "yaw" are indistinguishable without a specified reference point.

There are three axes of motion "x", "y", and "z".

1) Rotation on the x-axis is called "pitch". In an airplane this would be rotation on the axis that runs from wing-tip to wing-tip. Rotation on that axis moves the nose up or down - "pitch".
2) Rotation on the y-axis is called "roll". In an airplane this would be rotation on the axis that runs from nose to tail. Rotation on that axis "spins" the airplane or in our case spins the bullet.
3) Rotation on the z-axis is called "yaw" In an airplane this would be rotation on the axis that runs through the center of the plane top-to-bottom. Rotation on that axis moves the nose left and right.

The Berger simulation says that the plot is the relationship between pitch and yaw, meaning NOT the rotation or movement of the bullet around the line-of-flight, but rather how the left/right movement of the nose of the bullet bullet compares to the up/down movement (not the flight-path up/down, but the "wobble" up/down), of the bullet. I really question the application of this simulation to the idea of bullets "going to sleep". I know that's what Berger SAYS it is, I just think they are 1) Mistaken, or 2) Have incorrectly described the what the plot is. The nose of the bullet does not define the path of the bullet. The center of mass does. (There are those pesky laws of motion again.) Certainly the nose of a "pointy" bullet can influence the flight path, but the magnitude of that influence is not quantifiable unless you shoot the bullet in a vacuum because the instantaneous wind velocity and density will change from moment to moment which will in turn change the magnitude of the influence that the nose of the bullet has on the flight path.

What Berger's simulation COULD be pointing to (you can't tell from the explanation provided nor the graph), is that the point of a "pointy" bullet "moves" around for "a while" after it leaves the muzzle, and "settles down" some time later. IMPLYING that precision would 'follow' the bullet's nose. However, that's NOT what it shows.

What it does show, is that the left/right movement AS COMPARED TO THE UP/DOWN MOVEMENT changes with time. That means NOTHING. Keep in mind that the graph is left/right motion of the nose relative to the up/down motion of the nose NOT THE FLIGHT PATH. If the nose of the bullet was moving AN INCH left and right and AND INCH up and down, the graph would show ZERO RELATIVE MOTION. (By the way, there are a TON of assumptions in Bergers simulation, none of which are noted.)

Certainly less movement of the nose of a "pointy" bullet would suggest that precision would be better, but there's no proof or quantification of that assumption provided by the simulation.

Basically, all the Berger simulation "shows" is the THEORETICAL response of one end of a rotating cylinder to some initial perturbation. You can see that by spinning a top or toy gyro. But again, both the top and the gyro have fixed points of attachment to an immovable surface. That's not a trivial difference in the two systems under consideration.

Paul
Be nicer than necessary.

gitano

#21
Let me discuss the Berger simulation a little more, but separately. Let's examine what an individual point on the graph means.

On the graph,



at 3 yards the point being graphed is located at -3,0. That means that the point of the bullet was 3 degrees DIFFERENT in the left/right direction from the point of the bullet in the up/down direction. THERE IS NO INFORMATION ON HOW FAR OFF AXIS (line of flight) THE NOSE ACTUALLY IS. The point plotted is the position of the nose ONLY in the left/right direction RELATIVE to the position of the nose in the up/down direction. If the nose was 3 degrees off axis in the left/right direction and exactly on in the up/down direction. Unfortunately there are an infinite number of pairs of distances the two values could be that would produce a value of "-3" on the graph.

Now consider the graph three yards later at 6 yds,



Note that the point plotted is exactly at 0,0. What that means is that the distance that the nose is off of the line-of-flight in the up/down direction is exactly equal to the distance it is off of the line-of-flight in the left/right direction. However, IT DOES NOT MEAN THE NOSE OF THE BULLET IS COINCIDENT WITH THE LINE-OF-FLIGHT! The bullet could be completely SIDEWAYS at a 45 degree angle, and the point plotted would still be 0,0 because the position of the "yaw" to the "pitch" would still be equal so the difference would be 0! Furthermore, I have given Berger the benefit of the doubt in saying saying that the point plotted is relative to the "line-of-flight". There is NOTHING in the video that defines what the plotted point is in relation to.

Berger implies a certain 'sophistication' to the simulation by stating "6 degrees of freedom" (but doesn't state what they are). Degrees of freedom is a statistical term. Here are the "degrees of freedom" I can see in the graph:

1) Roll, (irrelevant if angular momentum or angular velocity is considered a "degeree of fredom")
2) Pitch,
3) Yaw,
4) Range, (not really a degree of freedom as it is a function of a fixed variable - MV and another fixed variable - ballistic coefficient.)
5) Angular momentum (derived from angular velocity, which is derived from twist rate and muzzle velocity, rendering neither it or roll, an actual "degree of freedom"),
6) Angular velocity (see "5")
7) Time

Twist rate and muzzle velocity are not degrees of freedom since they are fixed values - "fxed" is not "free"). Meaning that there are really only 5 "degrees of freedom" OF MOTION. This should not be confused with "degrees of freedom" for statistical purposes. In that case, fixing pitch as the independent variable removes one degree of freedom, making only three degrees of freedom for statistical purposes - time, pitch and yaw.

This simulation - as presented - IMPLIES a great deal and tells me NOTHING.


Paul
Be nicer than necessary.

recoil junky

I gotta go get my glasses and by that time I'll have to got to work.

I'll take notes

One quick thought though: Can a bullet really be unstable on each of it's three axis at the same time due to gs? IMO, no, and to me that is what Berger is saying it can do.

But like I said I gotta find my glasses so's I can read this better AND I gotta go to work.

RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

Nelsdou

I was too lazy to dig through my physics and mechanical dynamics books so I read this http://www.nennstiel-ruprecht.de/bullfly/index.htm#Contents Interesting read.

Nels
Put it into perspective; we live on a rock hurtling through space, what could be scarier than that?

gitano

An EXCELLENT article. May be the best I have ever seen so condensed.

I want to point out some important-to-our-discussion comments though.

Let's start with the last of it, the "two-arm" model. The most important comment made is:

"Then the bullet's TIP moves on a spiral-like (also described as helical) path as indicated in the drawing, while the CG remains attached to the center of the circle".

The CG is what defines the flight-path of the bullet, not the "tip". Put another way, the bullet's center of gravity doesn't rotate around the center point of the graph, only its tip does.

Further,

"This figure schematically visualizes the general angular motion of a spin-stabilized bullet close to the muzzle.

Also,

"Note that the magnitude of successive maximum yaw angles is less than its predecessors, as the bullet in the drawing is assumed to be dynamically stable (the maximum yaw angle decreases as the bullet continues to move on)."

Meaning that each instantaneous value of the calculated yaw angle is smaller than the one immediately before it, and

At muzzle exit (t=0) the yaw angle can be small, but increases to a maximum of approximately 1°, then decreases again to almost zero.

Which means that the TIP of the bullet is never more than 1 degree off-axis RELATIVE TO THE BULLET. Which is why you cannot detect this "tipping" at the target.

I would also point out that reading the text carefully is very important. The author is defining ALL of the forces acting on a bullet, BUT not all of those forces are even present  and he always points out which ones go to zero or are "insignificant". In the end, the ones that "count" are gravity and ballistic coefficient.

This fairly substantiates the thoeretical rejection of bullets "going to sleep", and is why I conceptually reject the concept but remain open-minded because of trustworthy anecdotal observations.

Paul
Be nicer than necessary.

recoil junky

I will need to reread the article a couple times to let my brain absorb all it's information.

I feel like Chris Farley in "Almost Heroes"  :Banghead:

One question (so far) in the FAQ's I did find "interesting" was "How fast does a bullet lose it's spin velocity?"

I think this needs further investigation as (IMO), "spin velocity" (RPM) has more to do with a bullet's flight than can be seen on doppler radar. IF we could do "shadowgraphs" for say the first 200 yards of a bullets flight we could probably see the nodes where the bullet has destabilized and restabilized because of RPM loss just as the top, driveshafts and tires do.

As Paul is hard headed with things mathematical and their ease of being proven "on paper" I'm as hard headed the other way. Which makes for some very interesting conversations by the way. I need physical proof and I've seen physical proof of a bullet "going to sleep". I guess the way for me to prove it is to line up targets say every 25 yards out to 200 yards and shoot a ten shot group without leaving the bench between shots and see where they all go. Now I need a flat place at least 250 yards long. In a building would be nice.

People said it was impossible for man to survive at speeds of more than 60 MPH, that we could never go faster than the speed of sound in the air OR ON LAND.

If there is someone who says it can't be done, there's someone who is going to go out and prove him wrong.

RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

gitano

#26
QuoteAs Paul is hard headed with things mathematical and their ease of being proven "on paper" I'm as hard headed the other way.

Let me clarify my actual position a little bit.

What I'm REALLY hard-headed about is have BOTH anecdotal observation and theory jibe. If they don't, something's amiss - either the theory needs adjusting or the anecdotal observation has a different explanation.

In this case, I'm leaning toward the latter. Not that some form of down-range stabilization doesn't necessarily take place, but rather exactly what the real explanation of the observations is.

Your proposed experiment sounds good, RJ, but if the down-range stabilization wasn't observed it wouldn't mean it doesn't take place. There are a whole herd of variables to consider. That's one of the reasons it hasn't been experimentally approached. It's too tough, (expensive and time-consuming), to prove unless you REALLY want to. For the competitive and "practical" shooters, the cause is irrelevant. All they need/want is a "fix", not an explanation, and the "fix" is usually simply slowing down the muzzle velocity.

In the "grand scheme of things" what I think is happening is that "muzzle blast", in all its various forms, is "perturbing" the bullet immediately after it leaves the muzzle, the rotational forces "force" it back into stability in "short order". The real question is what is "short order" as measured in yards/meters, not time.

As for the rpms and nodes of stability occurring down-range, I am quite certain there are none. The rotational velocity fundamentally doesn't change within small arms OR "large arm" ranges because the "shaft" (bullet) is rotating on an air bearing. "Nodal instability" is an issue ONLY at the initial point when the bullet leaves the muzzle. If the rotational velocity is near an "instability node", then the bullet will be unstable for a longer time, maybe long enough to show at 100 yds, and "settle down" beyond. That "settling down" is due to the stabilizing effects of rotational momentum, not changing rotational velocity. Therefore, there won't be an "opportunity" for the bullet to hit another "unstable" rotational velocity node before it hits the ground.

Paul
Be nicer than necessary.

recoil junky

Paul, us hard headed fellers gots' tah stick together. It makes for interesting dinner conversation. :greentongue: I think we're both on the same page, it's just that my page has been through the wash, is wrinkled and harder to read. :frown

 I wish I could better understand the math part. In Algebra I was , shall we say, not too good? All the formulas went right over my head. I could understand them if there were numbers instead of letters. When given a problem "solve for 'b'" I could do it using my own "formula"and get the answer right (most of the time). To me letters just don't add up. :D


"In the "grand scheme of things" what I think is happening is that "muzzle blast", in all its various forms, is "perturbing" the bullet immediately after it leaves the muzzle, the rotational forces "force" it back into stability in "short order". The real question is what is "short order" as measured in yards/meters, not time."
I agree.

I think I'm stuck on the RPM thing (in the sense of rotational forces) because that's what I understand. My theory is that the bullet is spinning so fast that it takes a smaller percentage of RPM change to hit a node of instability than say the drive shaft. I've seen an unbalanced drive shaft go through it's nodes and watched the tachometer when it nears and passes through one. Sometimes it take as little as 5 RPM to go from "smooth" to "vibrating" and back to "smooth" again.

 Lets say the drive shaft hits a node between 200 and 205 RPM. That's 2.5% (I think) of the RPM at that point. Now, see'ins as how a bullet's mass is much smaller than a drive shaft, wouldn't it take a far less percentage of RPM loss to "destabilize" it? Am I correct in thinking that a bullet, even though it's rotating on an "air bearing", will still lose RPM at a predictable rate over distance and hit a node of instability and smooth out in short order (distance)?

RJ
When you go afield, take the kids and please......................................wear your seatbelts.
Northwest Colorado.............Where the wapiti roam and deer and antelope run amuck. :undecided:  
Proud father of a soldier medic in The 82nd Airborne 325th AIR White Falcons :army:

gitano

QuoteNow, see'ins as how a bullet's mass is much smaller than a drive shaft, wouldn't it take a far less percentage of RPM loss to "destabilize" it?

and

QuoteAm I correct in thinking that a bullet, even though it's rotating on an "air bearing", will still lose RPM at a predictable rate over distance and hit a node of instability and smooth out in short order (distance)?

Are important sentences in your post.

First is the use of "percentages". When you do that, you "normalize" or "standardize" the effect, removing the differences in the masses of the two objects being compared. When you use the "percentage" term, I have to answer the second sentence/question "No".

Please don't interpret that response as "cute" or simply "playing with words". "Percentage" is the correct way to compare two "things" as different as a bullet and a drive shaft. If you hadn't used it, I would have. Let me digress for a moment to point to some of the significant differences between the two "systems".

1) The shaft doesn't ride on an air bearing. It's connected at both ends. That REALLY matters.
2) As far as I know, all drive shafts are hollow to save weight. Of course bullets are not hollow and in fact, higher densities are sought, at least most of the time. Hollow vs solid (mostly the rigidity of the 'shaft') makes a BIG difference in resonant frequency AND the response to hitting a resonant node.

Back from the digression, the primary reason that the percentage of rpms to reach a resonant node is significant in answering your question is the respective rotational velocities and momenta of the shaft and bullet. In other words, even though the mass of the bullet is so much less than the mass of the shaft, the angular moment is "equally" (not necessarily "equal", but certainly proportionally), small because the bullet is so much smaller in diameter. Therefore it is mathematically demonstrable, (and in this case, the math is the simple engineering of drive shafts), that the angular momentum between a drive shaft of a certain length (very important to resonance) and rotational speed and a bullet of certain length and "spin rate" could have the exact same "moment" of angular momentum. Meaning that the same percentage/proportion of change in rpm (angular velocity) would result in the same transition from resonant ("unstable") to non-resonant.

Let's take your initial conditions of starting the bullet off at a resonant node when it leaves the muzzle. Lat's say we also start the bullet "perturbed" by "muzzle blast". The force that is acting to stabilize the bullet is the same  - angular momentum - and in both cases, the result is the same. The angular momentum FORCES the bullet to "settle down" gyroscopically. The rpm of the bullet will never slow down enough to reach another "instability" (resonant) node, and I'm not sure that it can even be resonant since it is not "attached" to anything solid at either end.

Consider other "things" that you (the collective "you") are familiar with. All wind instruments. They make music by vibrating at resonant nodes. The different nodes are the different notes. The instrument is fixed at the player's mouth.

The classic vibrating wine glass. Vibrating at resonance either with a wet finger rubbing the rim or being impinged upon by sound at the resonant frequency. The glass is fixed at its base resting on the table. If it wasn't fixed, it wouldn't vibrate.

Consider the "music" we make when we blow across the top of a beer bottle. The "fixed" part of the system, without which there would be no "music" (resonance) possible is the bottom of the bottle.

So, I'm not certain that there even ARE "resonance" nodes for an unfixed shaft rotating on an air bearing. I can't envision what would allow "vibration".

Finally, let me try to make clear that I greatly disdain those "scientists" and "engineers" that can't explain simple phenomena without resorting to symbolic algebra. It is a common malady of those that know rules but don't know reality. When pressed, they always retreat into symbolic math because they know that in most cases, most regular Joes can't follow. I consider the scientists and engineers that so commonly take that path as cowards and bullies.

That's not to say that I don't use and rely on symbolic math. I do, and I do heavily. However, I try not to use it when I am explaining or discussing some natural phenomenon. It is my opinion that if symbolic math is the only method one has at their disposal to explain a natural phenomenon, then they need to learn more about what their arguing. "Ivory Tower" academics have spent a great deal of time learning and memorizing the "rules". One only has so much time. Time spent learning the "rules" doesn't leave time for "experience". The "guy" with the most tools in his toolbox is the one that knows the rules AND has lived long enough outside the womb of academia to have experience as well.

So much for my sermon for today.

Paul
Be nicer than necessary.

Nelsdou

OK, I reloaded my set with a slightly lighter charge and repeated my previous range session, this time shooting 4 foulers, a set of ten at 100 yds, then shooting 10 at 200 yds. The four foulers had the same boolit but had entirely different charge from a previous experiment, so I taped these over in the first round. The rifle used is a Yugo 24/47 with open sights.



The first set of 10 at 100 yds are the ones circled. The second set of 10 at 200 yds did not make the paper as I over-compensated for the lower charge and set my sight way too high, so the second 10 hit the cardboard about a foot above this target.  The numbered holes are from my 6.5x55  sporter using a 4X scope, 135 grain cast boolit, at 100 yds, and reflects a couple of scope adjustments.

Funny thing is the "group" of the second 10 at 200 yds is approximately the same as the 10 at 100 yds, which I think is somewhat a fluke. Trying to aim open sights at this paper at 200 yds with honest accuracy is a lot tougher that pining down a 12x12 inch gong at 220 yds.

Anyway, I think this particular cast boolit has good long range potential in a scoped rifle and obviously shoots flatter that I expected. A little more fiddling with the charge and the use of a scope should cut this group in half.

In an earlier post I mentioned seasoning the barrel with a number of foulers before this boolit might settle in. To see if that's the case this gun's barrel is not getting "cleaned" between further sessions of tuning this load.

Nels
Put it into perspective; we live on a rock hurtling through space, what could be scarier than that?

Jamie.270

Nels,
In an effort to "standardize" your target's bull reference in your sight picture, you might try picking up some self adhesive black dots.
I would use 2" at the 100yd mark, and 4" dots at the 200yd range.
This will give you a similar sight picture to center on, and I believe a truer group size, relative to the ranges in question.

Jamie
QuoteRestrictive gun laws that leave good people helpless, don\'t have the power to render bad people harmless.

To believe otherwise is folly. --  Me

Nelsdou

Jamie, I hear what you are saying, particularly at long distance but the 'ol eyeball strain w/ iron sights is getting more limiting in duration. The M24/47 Yugo is my test rifle for cast and gives me results pretty quick if a cast load is worth pursing any farther.

In a week or two I should have my 8mm wildcat barreled in 10 twist on a scoped receiver. This cast bullet should be a dandy to try out for a 200-300 yd range.

Nels
Put it into perspective; we live on a rock hurtling through space, what could be scarier than that?

gitano

I appreciate the reports, Nels.

I really don't have any suggestions - not that you were seeking any.

I agree that is seems this bullet may be "made" for "long range". I look forward to seeing what it does on the wildcat with a 'scope. Is that wildcat the "Kurz" you were talking about some time back?

Paul
Be nicer than necessary.

Nelsdou

Yep, matter of fact got my barrel back today with the chamber cut, threaded, and crowned. :grin:  Now I can get on with fire-forming some brass. Really glad I got a Go-guage with the reamer so setting up my dies and headspace on the Savage should be a snap.

In the coming weeks I'll post some pics on the project.

Nels
Put it into perspective; we live on a rock hurtling through space, what could be scarier than that?

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